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# [Question 2] ISC 2016 Computer Practical Paper Solved – Sorting Non-Boundary Matrix Elements

#### Question:

Write a program to declare a square matrix A[][] of order (M x M) where ‘M’ must be greater than 3 and less than 10. Allow the user to input positive integers into this matrix. Perform the following tasks on the matrix:

(a) Sort the non-boundary elements in ascending order using any standard sorting technique and rearrange them in the matrix.
(b) Calculate the sum of both the diagonals.
(c) Display the original matrix, rearranged matrix and only the diagonal elements of the rearranged matrix with their sum.

Test your program with the sample data and some random data:

Example 1

INPUT :M = 4

```9	2	1	5
8	13	8	4
15	6	3	11
7	12	23	8
```

OUTPUT:

ORIGINAL MATRIX

```9	2	1	5
8	13	8	4
15	6	3	11
7	12	23	8
```

REARRANGED MATRIX

```9	2	1	5
8	3	6	4
15	8	13	11
7	12	23	8
```

DIAGONAL ELEMENTS

```9			5
3	6
8	13
7			8
```

SUM OF THE DIAGONAL ELEMENTS = 59

#### Programming Code:

```/**
* The class SortNonBoundary_ISC2016 inputs a square matrix and
* sorts the non-boundary elements in ascending order
* @author : www.guideforschool.com
* @Program Type : BlueJ Program - Java
* @Question Year : ISC Practical 2016 Question 2
*/

import java.util.*;
class SortNonBoundary_ISC2016
{
int A[][],B[],m,n;

void input() //Function for taking all the necessary inputs
{
Scanner sc = new Scanner(System.in);
System.out.print("Enter the size of the square matrix : ");
m=sc.nextInt();
if(m<4 || m>10)
{
System.out.println("Invalid Range");
System.exit(0);
}
else
{
A = new int[m][m];
n = (m-2)*(m-2);
B = new int[n]; //Array to store Non-Boundary Elements

System.out.println("Enter the elements of the Matrix : ");
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
System.out.print("Enter a value : ");
A[i][j]=sc.nextInt();
}
}
}
}

/* The below function stores Non-Boundary elements
* from array A[][] to array B[] if s = 1
* else stores the Non-Boundary elements in array A[][] from array B[]
*/
void convert(int s)
{
int x=0;
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
if(i != 0 && j != 0 && i != m-1 && j != m-1)
{
if(s==1)
B[x] = A[i][j];
else
A[i][j] = B[x];
x++;
}
}
}
}

void sortArray() //Function for sorting Non-Boundary elements stored in array B[]
{
int c = 0;
for(int i=0; i<n-1; i++)
{
for(int j=i+1; j<n; j++)
{
if(B[i]>B[j])
{
c = B[i];
B[i] = B[j];
B[j] = c;
}
}
}
}

void printArray() //Function for printing the array A[][]
{
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
System.out.print(A[i][j]+"\t");
}
System.out.println();
}
}

void printDiagonal() //Function for printing the diagonal elements and their sum
{
int sum = 0;
for(int i=0;i<m;i++)
{
for(int j=0;j<m;j++)
{
if(i==j || (i+j)==m-1)
{
System.out.print(A[i][j]+"\t");
sum = sum + A[i][j];
}
else
System.out.print("\t");
}
System.out.println();
}
System.out.println("Sum of the Diagonal Elements : "+sum);
}

public static void main(String args[])
{
SortNonBoundary_ISC2016 ob = new SortNonBoundary_ISC2016();
ob.input();
System.out.println("*********************");
System.out.println("The original matrix:");
System.out.println("*********************");
ob.printArray(); //Printing the original array
ob.convert(1); //Storing Non-Boundary elements to a 1-D array
ob.sortArray(); //Sorting the 1-D array (i.e. Non-Diagonal Elements)
ob.convert(2); //Storing the sorted Non-Boundary elements back to original 2-D array

System.out.println("*********************");
System.out.println("The Rearranged matrix:");
System.out.println("*********************");
ob.printArray(); //Printing the rearranged array
System.out.println("*********************");
System.out.println("The Diagonal Elements:");
System.out.println("*********************");
ob.printDiagonal(); //Printing the diagonal elements and their sum
}
}
```

#### Output:

```Enter the size of the square matrix : 4
Enter the elements of the Matrix :
Enter a value : 9
Enter a value : 2
Enter a value : 1
Enter a value : 5
Enter a value : 8
Enter a value : 13
Enter a value : 8
Enter a value : 4
Enter a value : 15
Enter a value : 6
Enter a value : 3
Enter a value : 11
Enter a value : 7
Enter a value : 12
Enter a value : 23
Enter a value : 8
*********************
The original matrix:
*********************
9	2	1	5
8	13	8	4
15	6	3	11
7	12	23	8
*********************
The Rearranged matrix:
*********************
9	2	1	5
8	3	6	4
15	8	13	11
7	12	23	8
*********************
The Diagonal Elements:
*********************
9			5
3	6
8	13
7			8
Sum of the Diagonal Elements : 59

```

## Infix Postfix Prefix Conversion – Correct Method (ISC Computer Science)

In this video we discuss about the correct way of converting an Infix Expression to Postfix and Prefix.

1. Sir shouldn’t the sum be 79 for this example?

• No.
9 + 5 + 3 + 6 + 8 + 13 + 7 + 8 = 59

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