**Question:**

Write a Program in Java to input a number and check whether it is a **Disarium Number** or not.

**Note:** A number will be called DISARIUM if sum of its digits powered with their respective position is equal to the original number.

**For example** 135 is a DISARIUM

(Workings 1^{1}+3^{2}+5^{3} = 135, some other **DISARIUM** are 89, 175, 518 etc)

**Programming Code:**

/** * The class Disarium inputs a number and checks whether * it is a Disarium number or not * @author : www.javaforschool.com * @Program Type : BlueJ Program - Java */ import java.io.*; class Disarium { public static void main(String[] args)throws IOException { BufferedReader br=new BufferedReader (new InputStreamReader(System.in)); System.out.print("Enter a number : "); int n = Integer.parseInt(br.readLine()); int copy = n, d = 0, sum = 0; String s = Integer.toString(n); //converting the number into a String int len = s.length(); //finding the length of the number i.e. no.of digits while(copy>0) { d = copy % 10; //extracting the last digit sum = sum + (int)Math.pow(d,len); len--; copy = copy / 10; } if(sum == n) System.out.println(n+" is a Disarium Number."); else System.out.println(n+" is not a Disarium Number."); } }

**Output:**

Enter a Number : 135

135 is a Disarium Number.

Enter a Number : 219

219 is not a Disarium Number.

Enter a Number : 89

89 is a Disarium Number.

Good and helpful for me

Yes please keep sending this type of interesting programs.

please keep sending such interesting programs…..thank you